3.5.67 \(\int \frac {(e x)^{5/2} (A+B x)}{(a+c x^2)^{3/2}} \, dx\) [467]

3.5.67.1 Optimal result
3.5.67.2 Mathematica [C] (verified)
3.5.67.3 Rubi [A] (verified)
3.5.67.4 Maple [A] (verified)
3.5.67.5 Fricas [C] (verification not implemented)
3.5.67.6 Sympy [C] (verification not implemented)
3.5.67.7 Maxima [F]
3.5.67.8 Giac [F]
3.5.67.9 Mupad [F(-1)]

3.5.67.1 Optimal result

Integrand size = 24, antiderivative size = 326 \[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}+\frac {5 B e^2 \sqrt {e x} \sqrt {a+c x^2}}{3 c^2}+\frac {3 A e^3 x \sqrt {a+c x^2}}{c^{3/2} \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )}-\frac {3 \sqrt [4]{a} A e^3 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}-\frac {\sqrt [4]{a} \left (5 \sqrt {a} B-9 A \sqrt {c}\right ) e^3 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{6 c^{9/4} \sqrt {e x} \sqrt {a+c x^2}} \]

output
-e*(e*x)^(3/2)*(B*x+A)/c/(c*x^2+a)^(1/2)+3*A*e^3*x*(c*x^2+a)^(1/2)/c^(3/2) 
/(a^(1/2)+x*c^(1/2))/(e*x)^(1/2)+5/3*B*e^2*(e*x)^(1/2)*(c*x^2+a)^(1/2)/c^2 
-3*a^(1/4)*A*e^3*(cos(2*arctan(c^(1/4)*x^(1/2)/a^(1/4)))^2)^(1/2)/cos(2*ar 
ctan(c^(1/4)*x^(1/2)/a^(1/4)))*EllipticE(sin(2*arctan(c^(1/4)*x^(1/2)/a^(1 
/4))),1/2*2^(1/2))*(a^(1/2)+x*c^(1/2))*x^(1/2)*((c*x^2+a)/(a^(1/2)+x*c^(1/ 
2))^2)^(1/2)/c^(7/4)/(e*x)^(1/2)/(c*x^2+a)^(1/2)-1/6*a^(1/4)*e^3*(cos(2*ar 
ctan(c^(1/4)*x^(1/2)/a^(1/4)))^2)^(1/2)/cos(2*arctan(c^(1/4)*x^(1/2)/a^(1/ 
4)))*EllipticF(sin(2*arctan(c^(1/4)*x^(1/2)/a^(1/4))),1/2*2^(1/2))*(5*B*a^ 
(1/2)-9*A*c^(1/2))*(a^(1/2)+x*c^(1/2))*x^(1/2)*((c*x^2+a)/(a^(1/2)+x*c^(1/ 
2))^2)^(1/2)/c^(9/4)/(e*x)^(1/2)/(c*x^2+a)^(1/2)
 
3.5.67.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.04 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.37 \[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=\frac {e^2 \sqrt {e x} \left (5 a B-3 A c x+2 B c x^2-5 a B \sqrt {1+\frac {c x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},-\frac {c x^2}{a}\right )+3 A c x \sqrt {1+\frac {c x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {7}{4},-\frac {c x^2}{a}\right )\right )}{3 c^2 \sqrt {a+c x^2}} \]

input
Integrate[((e*x)^(5/2)*(A + B*x))/(a + c*x^2)^(3/2),x]
 
output
(e^2*Sqrt[e*x]*(5*a*B - 3*A*c*x + 2*B*c*x^2 - 5*a*B*Sqrt[1 + (c*x^2)/a]*Hy 
pergeometric2F1[1/4, 1/2, 5/4, -((c*x^2)/a)] + 3*A*c*x*Sqrt[1 + (c*x^2)/a] 
*Hypergeometric2F1[1/2, 3/4, 7/4, -((c*x^2)/a)]))/(3*c^2*Sqrt[a + c*x^2])
 
3.5.67.3 Rubi [A] (verified)

Time = 0.44 (sec) , antiderivative size = 320, normalized size of antiderivative = 0.98, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {549, 27, 552, 27, 556, 555, 1512, 27, 761, 1510}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx\)

\(\Big \downarrow \) 549

\(\displaystyle \frac {e^2 \int \frac {\sqrt {e x} (3 A+5 B x)}{2 \sqrt {c x^2+a}}dx}{c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {e^2 \int \frac {\sqrt {e x} (3 A+5 B x)}{\sqrt {c x^2+a}}dx}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 552

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {2 e \int \frac {5 a B-9 A c x}{2 \sqrt {e x} \sqrt {c x^2+a}}dx}{3 c}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {e \int \frac {5 a B-9 A c x}{\sqrt {e x} \sqrt {c x^2+a}}dx}{3 c}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 556

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {e \sqrt {x} \int \frac {5 a B-9 A c x}{\sqrt {x} \sqrt {c x^2+a}}dx}{3 c \sqrt {e x}}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 555

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {2 e \sqrt {x} \int \frac {5 a B-9 A c x}{\sqrt {c x^2+a}}d\sqrt {x}}{3 c \sqrt {e x}}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 1512

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {2 e \sqrt {x} \left (\sqrt {a} \left (5 \sqrt {a} B-9 A \sqrt {c}\right ) \int \frac {1}{\sqrt {c x^2+a}}d\sqrt {x}+9 \sqrt {a} A \sqrt {c} \int \frac {\sqrt {a}-\sqrt {c} x}{\sqrt {a} \sqrt {c x^2+a}}d\sqrt {x}\right )}{3 c \sqrt {e x}}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {2 e \sqrt {x} \left (\sqrt {a} \left (5 \sqrt {a} B-9 A \sqrt {c}\right ) \int \frac {1}{\sqrt {c x^2+a}}d\sqrt {x}+9 A \sqrt {c} \int \frac {\sqrt {a}-\sqrt {c} x}{\sqrt {c x^2+a}}d\sqrt {x}\right )}{3 c \sqrt {e x}}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 761

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {2 e \sqrt {x} \left (9 A \sqrt {c} \int \frac {\sqrt {a}-\sqrt {c} x}{\sqrt {c x^2+a}}d\sqrt {x}+\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (5 \sqrt {a} B-9 A \sqrt {c}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 \sqrt [4]{c} \sqrt {a+c x^2}}\right )}{3 c \sqrt {e x}}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

\(\Big \downarrow \) 1510

\(\displaystyle \frac {e^2 \left (\frac {10 B \sqrt {e x} \sqrt {a+c x^2}}{3 c}-\frac {2 e \sqrt {x} \left (\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (5 \sqrt {a} B-9 A \sqrt {c}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{2 \sqrt [4]{c} \sqrt {a+c x^2}}+9 A \sqrt {c} \left (\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{\sqrt [4]{c} \sqrt {a+c x^2}}-\frac {\sqrt {x} \sqrt {a+c x^2}}{\sqrt {a}+\sqrt {c} x}\right )\right )}{3 c \sqrt {e x}}\right )}{2 c}-\frac {e (e x)^{3/2} (A+B x)}{c \sqrt {a+c x^2}}\)

input
Int[((e*x)^(5/2)*(A + B*x))/(a + c*x^2)^(3/2),x]
 
output
-((e*(e*x)^(3/2)*(A + B*x))/(c*Sqrt[a + c*x^2])) + (e^2*((10*B*Sqrt[e*x]*S 
qrt[a + c*x^2])/(3*c) - (2*e*Sqrt[x]*(9*A*Sqrt[c]*(-((Sqrt[x]*Sqrt[a + c*x 
^2])/(Sqrt[a] + Sqrt[c]*x)) + (a^(1/4)*(Sqrt[a] + Sqrt[c]*x)*Sqrt[(a + c*x 
^2)/(Sqrt[a] + Sqrt[c]*x)^2]*EllipticE[2*ArcTan[(c^(1/4)*Sqrt[x])/a^(1/4)] 
, 1/2])/(c^(1/4)*Sqrt[a + c*x^2])) + (a^(1/4)*(5*Sqrt[a]*B - 9*A*Sqrt[c])* 
(Sqrt[a] + Sqrt[c]*x)*Sqrt[(a + c*x^2)/(Sqrt[a] + Sqrt[c]*x)^2]*EllipticF[ 
2*ArcTan[(c^(1/4)*Sqrt[x])/a^(1/4)], 1/2])/(2*c^(1/4)*Sqrt[a + c*x^2])))/( 
3*c*Sqrt[e*x])))/(2*c)
 

3.5.67.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 549
Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Sym 
bol] :> Simp[e*(e*x)^(m - 1)*(c + d*x)*((a + b*x^2)^(p + 1)/(2*b*(p + 1))), 
 x] - Simp[e^2/(2*b*(p + 1))   Int[(e*x)^(m - 2)*(c*(m - 1) + d*m*x)*(a + b 
*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && LtQ[p, -1] && GtQ[m, 
1]
 

rule 552
Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Sym 
bol] :> Simp[d*(e*x)^m*((a + b*x^2)^(p + 1)/(b*(m + 2*p + 2))), x] - Simp[e 
/(b*(m + 2*p + 2))   Int[(e*x)^(m - 1)*(a + b*x^2)^p*Simp[a*d*m - b*c*(m + 
2*p + 2)*x, x], x], x] /; FreeQ[{a, b, c, d, e, p}, x] && GtQ[m, 0] && NeQ[ 
m + 2*p + 2, 0] && (IntegerQ[p] || IntegersQ[2*m, 2*p])
 

rule 555
Int[((f_) + (g_.)*(x_))/(Sqrt[x_]*Sqrt[(a_) + (c_.)*(x_)^2]), x_Symbol] :> 
Simp[2   Subst[Int[(f + g*x^2)/Sqrt[a + c*x^4], x], x, Sqrt[x]], x] /; Free 
Q[{a, c, f, g}, x]
 

rule 556
Int[((c_) + (d_.)*(x_))/(Sqrt[(e_)*(x_)]*Sqrt[(a_) + (b_.)*(x_)^2]), x_Symb 
ol] :> Simp[Sqrt[x]/Sqrt[e*x]   Int[(c + d*x)/(Sqrt[x]*Sqrt[a + b*x^2]), x] 
, x] /; FreeQ[{a, b, c, d, e}, x]
 

rule 761
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[( 
1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))* 
EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
 

rule 1510
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = 
 Rt[c/a, 4]}, Simp[(-d)*x*(Sqrt[a + c*x^4]/(a*(1 + q^2*x^2))), x] + Simp[d* 
(1 + q^2*x^2)*(Sqrt[(a + c*x^4)/(a*(1 + q^2*x^2)^2)]/(q*Sqrt[a + c*x^4]))*E 
llipticE[2*ArcTan[q*x], 1/2], x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, c, d, e 
}, x] && PosQ[c/a]
 

rule 1512
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = 
 Rt[c/a, 2]}, Simp[(e + d*q)/q   Int[1/Sqrt[a + c*x^4], x], x] - Simp[e/q 
 Int[(1 - q*x^2)/Sqrt[a + c*x^4], x], x] /; NeQ[e + d*q, 0]] /; FreeQ[{a, c 
, d, e}, x] && PosQ[c/a]
 
3.5.67.4 Maple [A] (verified)

Time = 1.56 (sec) , antiderivative size = 308, normalized size of antiderivative = 0.94

method result size
default \(-\frac {e^{2} \sqrt {e x}\, \left (9 A \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) a c -18 A \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, E\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) a c +5 B \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-a c}\, a -4 B \,c^{2} x^{3}+6 A \,c^{2} x^{2}-10 a B c x \right )}{6 x \sqrt {c \,x^{2}+a}\, c^{3}}\) \(308\)
elliptic \(\frac {\sqrt {e x}\, \sqrt {\left (c \,x^{2}+a \right ) e x}\, \left (-\frac {2 x e c \left (\frac {e^{2} A x}{2 c^{2}}-\frac {e^{2} B a}{2 c^{3}}\right )}{\sqrt {\left (x^{2}+\frac {a}{c}\right ) x e c}}+\frac {2 B \,e^{2} \sqrt {c e \,x^{3}+a e x}}{3 c^{2}}-\frac {5 B a \,e^{3} \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{6 c^{3} \sqrt {c e \,x^{3}+a e x}}+\frac {3 A \,e^{3} \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, \left (-\frac {2 \sqrt {-a c}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}+\frac {\sqrt {-a c}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}\right )}{2 c^{2} \sqrt {c e \,x^{3}+a e x}}\right )}{e x \sqrt {c \,x^{2}+a}}\) \(377\)
risch \(\frac {2 B x \sqrt {c \,x^{2}+a}\, e^{3}}{3 c^{2} \sqrt {e x}}+\frac {\left (-\frac {4 B a \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c \sqrt {c e \,x^{3}+a e x}}+\frac {3 A \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, \left (-\frac {2 \sqrt {-a c}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}+\frac {\sqrt {-a c}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}\right )}{\sqrt {c e \,x^{3}+a e x}}-3 a \left (-\frac {2 c e x \left (-\frac {A x}{2 a e}+\frac {B}{2 e c}\right )}{\sqrt {\left (x^{2}+\frac {a}{c}\right ) x e c}}-\frac {B \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{2 c \sqrt {c e \,x^{3}+a e x}}-\frac {A \sqrt {-a c}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}\, \sqrt {-\frac {x c}{\sqrt {-a c}}}\, \left (-\frac {2 \sqrt {-a c}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}+\frac {\sqrt {-a c}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a c}}{c}\right ) c}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )}{c}\right )}{2 a \sqrt {c e \,x^{3}+a e x}}\right )\right ) e^{3} \sqrt {\left (c \,x^{2}+a \right ) e x}}{3 c^{2} \sqrt {e x}\, \sqrt {c \,x^{2}+a}}\) \(647\)

input
int((e*x)^(5/2)*(B*x+A)/(c*x^2+a)^(3/2),x,method=_RETURNVERBOSE)
 
output
-1/6*e^2/x*(e*x)^(1/2)*(9*A*((c*x+(-a*c)^(1/2))/(-a*c)^(1/2))^(1/2)*2^(1/2 
)*((-c*x+(-a*c)^(1/2))/(-a*c)^(1/2))^(1/2)*(-x/(-a*c)^(1/2)*c)^(1/2)*Ellip 
ticF(((c*x+(-a*c)^(1/2))/(-a*c)^(1/2))^(1/2),1/2*2^(1/2))*a*c-18*A*((c*x+( 
-a*c)^(1/2))/(-a*c)^(1/2))^(1/2)*2^(1/2)*((-c*x+(-a*c)^(1/2))/(-a*c)^(1/2) 
)^(1/2)*(-x/(-a*c)^(1/2)*c)^(1/2)*EllipticE(((c*x+(-a*c)^(1/2))/(-a*c)^(1/ 
2))^(1/2),1/2*2^(1/2))*a*c+5*B*((c*x+(-a*c)^(1/2))/(-a*c)^(1/2))^(1/2)*2^( 
1/2)*((-c*x+(-a*c)^(1/2))/(-a*c)^(1/2))^(1/2)*(-x/(-a*c)^(1/2)*c)^(1/2)*El 
lipticF(((c*x+(-a*c)^(1/2))/(-a*c)^(1/2))^(1/2),1/2*2^(1/2))*(-a*c)^(1/2)* 
a-4*B*c^2*x^3+6*A*c^2*x^2-10*a*B*c*x)/(c*x^2+a)^(1/2)/c^3
 
3.5.67.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.10 (sec) , antiderivative size = 143, normalized size of antiderivative = 0.44 \[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=-\frac {5 \, {\left (B a c e^{2} x^{2} + B a^{2} e^{2}\right )} \sqrt {c e} {\rm weierstrassPInverse}\left (-\frac {4 \, a}{c}, 0, x\right ) + 9 \, {\left (A c^{2} e^{2} x^{2} + A a c e^{2}\right )} \sqrt {c e} {\rm weierstrassZeta}\left (-\frac {4 \, a}{c}, 0, {\rm weierstrassPInverse}\left (-\frac {4 \, a}{c}, 0, x\right )\right ) - {\left (2 \, B c^{2} e^{2} x^{2} - 3 \, A c^{2} e^{2} x + 5 \, B a c e^{2}\right )} \sqrt {c x^{2} + a} \sqrt {e x}}{3 \, {\left (c^{4} x^{2} + a c^{3}\right )}} \]

input
integrate((e*x)^(5/2)*(B*x+A)/(c*x^2+a)^(3/2),x, algorithm="fricas")
 
output
-1/3*(5*(B*a*c*e^2*x^2 + B*a^2*e^2)*sqrt(c*e)*weierstrassPInverse(-4*a/c, 
0, x) + 9*(A*c^2*e^2*x^2 + A*a*c*e^2)*sqrt(c*e)*weierstrassZeta(-4*a/c, 0, 
 weierstrassPInverse(-4*a/c, 0, x)) - (2*B*c^2*e^2*x^2 - 3*A*c^2*e^2*x + 5 
*B*a*c*e^2)*sqrt(c*x^2 + a)*sqrt(e*x))/(c^4*x^2 + a*c^3)
 
3.5.67.6 Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 46.87 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.29 \[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=\frac {A e^{\frac {5}{2}} x^{\frac {7}{2}} \Gamma \left (\frac {7}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, \frac {7}{4} \\ \frac {11}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {3}{2}} \Gamma \left (\frac {11}{4}\right )} + \frac {B e^{\frac {5}{2}} x^{\frac {9}{2}} \Gamma \left (\frac {9}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, \frac {9}{4} \\ \frac {13}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {3}{2}} \Gamma \left (\frac {13}{4}\right )} \]

input
integrate((e*x)**(5/2)*(B*x+A)/(c*x**2+a)**(3/2),x)
 
output
A*e**(5/2)*x**(7/2)*gamma(7/4)*hyper((3/2, 7/4), (11/4,), c*x**2*exp_polar 
(I*pi)/a)/(2*a**(3/2)*gamma(11/4)) + B*e**(5/2)*x**(9/2)*gamma(9/4)*hyper( 
(3/2, 9/4), (13/4,), c*x**2*exp_polar(I*pi)/a)/(2*a**(3/2)*gamma(13/4))
 
3.5.67.7 Maxima [F]

\[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=\int { \frac {{\left (B x + A\right )} \left (e x\right )^{\frac {5}{2}}}{{\left (c x^{2} + a\right )}^{\frac {3}{2}}} \,d x } \]

input
integrate((e*x)^(5/2)*(B*x+A)/(c*x^2+a)^(3/2),x, algorithm="maxima")
 
output
integrate((B*x + A)*(e*x)^(5/2)/(c*x^2 + a)^(3/2), x)
 
3.5.67.8 Giac [F]

\[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=\int { \frac {{\left (B x + A\right )} \left (e x\right )^{\frac {5}{2}}}{{\left (c x^{2} + a\right )}^{\frac {3}{2}}} \,d x } \]

input
integrate((e*x)^(5/2)*(B*x+A)/(c*x^2+a)^(3/2),x, algorithm="giac")
 
output
integrate((B*x + A)*(e*x)^(5/2)/(c*x^2 + a)^(3/2), x)
 
3.5.67.9 Mupad [F(-1)]

Timed out. \[ \int \frac {(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx=\int \frac {{\left (e\,x\right )}^{5/2}\,\left (A+B\,x\right )}{{\left (c\,x^2+a\right )}^{3/2}} \,d x \]

input
int(((e*x)^(5/2)*(A + B*x))/(a + c*x^2)^(3/2),x)
 
output
int(((e*x)^(5/2)*(A + B*x))/(a + c*x^2)^(3/2), x)